Subject:- SA-I-CGPA Revised (Unit I Slope & Deflection) / SOM-CGPA (Unit VI Deflection of Beams)
b) Mohr and manderla
c) Bernoulli
d) Maxwell
Answer: b
Explanation: This method was developed by mohr and manderla.
A simply supported beam with a uniform load of W and a point load P is there.
Length of beam is L. EI is given. Left point is A and right point is B.
2.
What is the Degree of freedom of this beam?
a) 3
b) 1
c) 2
d) 4
Answer: a
Explanation: Rotation at both ends and relative displacement in y direction due
to settlement of one of the ends.
3.
If point A goes down and point B goes up, then this will be:-
a) Positive rotation
b) Can’t say
c) Depends upon magnitude
d) Negative rotation
Answer: d
Explanation: It will cause span’s cord angle to rotate anti-clockwise.
Node B is kept fixed while node A is rotated by θA.
4. If
point A goes down and point B goes up, then What will be MBA in this
case?
a) 2EI θA/L
b) EI θA/L
c) 3EI θA/L
d) 4EI θA/L
Answer: a
Explanation: Use conjugate beam method and since displacement at both ends is
zero, equate both end moments of conjugate beam to zero.
5. If
point A goes down and point B goes up, then What will be MAB in this
case?
a) EI θA/L
b) 4EI θA/L
c) 2EI θA/L
d) 3EI θA/L
Answer: b
Explanation: Use conjugate beam method and since displacement at both ends is
zero, equate both end moments of conjugate beam to zero.
Node A is kept fixed while node B is rotated by θB.
6. A cantilever beam AB having
span 3m with fixity at A and subjected to point load 9kN at B, what will be the
maximum slope, if EI is constant.
a) -40.5/EI
b) +40.5/EI
c) 81/EI
d) 121.5/EI
Answer: a
7. A cantilever beam AB having
span 3m with fixity at A and subjected to point load 9kN at B, what will be the
deflection slope, if EI is constant.
a) -40.5/EI
b) +40.5/EI
c) 81/EI
d) 121.5/EI
Answer: c
8.
What will be the difference in moment acting at both the ends?
a) EI Δ/L2
b) 2EI Δ/L2
c) 3EI Δ/L2
d) 0
Answer: d
Explanation: Both ends are not rotating.
9.
What will be the difference in shear force acting at both the ends?
a) EI Δ/L2
b) 2EI Δ/L2
c) 3EI Δ/L2
d) 0
Answer: d
Explanation: Both ends are not rotating.
10.
What will be the value of MAB?
a) -2EI Δ/L2
b) -4EI Δ/L2
c) -6EI Δ/L2
d) 0
Answer: c
Explanation: Use conjugate beam and equate MBA to Δ
11. Cantilever beam
AB with fixity at B of span L is subjected to udl throughout the span, what
will be the slope at A
a) –wL3/6EI
b) + wL3/6EI
c) wL4/8EI
d) WL3/8EI
Answer: a
12. Cantilever beam
AB with fixity at B of span L is subjected to udl throughout the span, what
will be the deflection at A
a) –wL3/6EI
b) + wL3/6EI
c) wL4/8EI
d) WL3/8EI
Answer: c
13. Simply
supported beam AB of span L is subjected to udl throughout the span, what will
be the slope at A
a) –wL3/24EI
b) + wL3/24EI
c) 5wL4/384EI
d) WL3/48EI
Answer: b
14. Simply
supported beam AB of span L is subjected to central clockwise couple M, what
will be the slope at A
a) –ML/24EI
b) +ML/24EI
c) ML4/8EI
d) WL3/8EI
Answer: a
15. Cantilever beam
AB with fixity at B of span L is subjected to clockwise couple at free end (MA),
what will be the slope at A
a) –MAL/3EI
b) +MAL/3EI
c) –MAL2/2EI
d) +MAL2/2EI
Answer: b
16. What will be the maximum deflection in a simply
supported beam AB of span 6m subjected to udl 12kN/m over span with constant
EI.
a) 202.5/EI
b) 200/EI
c) 108/EI
d) 102/EI
Answer: a
17. What will be the maximum slope in a simply supported
beam AB of span 6m subjected to udl 12kN/m over span with constant EI.
a) 202.5/EI
b) 200/EI
c) 108/EI
d) 102/EI
Answer: c
18. What will be the maximum deflection in a simply
supported beam AB of span 6m subjected to central point load 9kN over span with
constant EI.
a) 20.25/EI
b) 21.25/EI
c) 40.5/EI
d) 41.5/EI
Answer: c
19. What will be the maximum Slope in a simply supported
beam AB of span 6m subjected to central point load 9kN over span with constant
EI.
a) 20.25/EI
b) 21.25/EI
c) 40.5/EI
d) 41.5/EI
Answer: a
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