Miscellaneous MCQ's on RCC Beam Design Part-II

Continued..Miscellaneous MCQ's on RCC Beam Design

24) According to IS 456:2000 for design purpose the design stress in concrete is given by a) 0.67 fck b) 0.67 fck x 1.5 c) 0.446 fck d) Fck Ans:- choice (c) 25) The basic assumptions concerned in the analysis at the ultimate limit state of flexure (Cl. 38.1 of the Code) are a) Plane sections normal to the beam axis stay plane when bending b) The maximum compressive strain in concrete (at the outmost fibre) ecu shall be taken as 0.0035 in bending. c) The maximum compressive strain at the level of tensile steel shall be taken as 0.002+(0.87fy/Es) d) All are the assupmtions Ans:- correct choice (d) 26) The value of xu,max for M20 and Fe415 grade is, a) 0.53d b) 0.48d c) 0.46d d) 0.44d Ans:- Correct Choice (b) 27) Limiting values of Pt,lim for M20 and Fe500 grade is a) 0.961% b) 0.759% c) 1.201% d) 0.949% Ans:- choice (b) 28) Limiting values of Pt,lim for M20 and Fe415 grade is a) 0.961% b) 0.759% c) 1.201% d) 0.949% Ans:- choice (a) 29) Limiting Value of mu,lim/bd2 in MPa, for M20 and Fe250 grade is, a) 2.996 b) 2.777 c) 2.675 d) None of these Ans:- choice (a) 30) Limiting Value of Mu,lim/bd2 in MPa, for M20 and Fe415 grade is, a) 2.996 b) 2.777 c) 2.675 d) None of the above Ans:- correct choice (b) 31) In __________the steel percentage is over then limiting percentage due to that N-A falls below the balanced N-A and xu > xu,max a) Balanced section b) Under-reinforced section c) Over-reinforced section d) Any of these Ans:- choice (c) 32) The moment of resistance of a singly RC beam of two hundred millimeter breadth 400mm effective depth, reinforced with 3-16 millimeter diameter bars of Fe 415 steel. Take M20 grade of concrete, is a) 73.48kNm b) 202kNm c) 601kNm d) None of these Ans:- correct choice (a) 33) The depth of Neutral axis of a singly concrete beam of two hundred millimeter breadth 400mm effective depth, strengthened with 3-16 millimeter diameter bars of Fe 415 steel. Take M20 grade of concrete, is a) 73.48 mm b) 192 mm c) 603.19 mm d) 151.24 mm Ans:- correct choice (d) 34) The limiting depth of Neutral axis of a RC beam of two hundred millimeter breadth 400mm effective depth, strengthened with 3-16 millimeter diameter bars of Fe 415 steel. Take M20 grade of concrete, is a) 73.48 mm b) 192 mm c) 603.19 mm d) 151.24 mm Ans:- correct choice (b) 35) IS 456 stipulates the basic ratios of span to effective depth of beams for span up to 10 m as, for cantilever a) 7 b) 20 c) 26 d) 32 Ans:- choice (a) 36) IS 456 stipulates the basic ratios of span to effective depth of beams for span up to 10 m as, for hinged/simply Supported a) 7 b) 20 c) 26 d) 32 Ans:- choice (b) 37) IS 456 stipulates the basic ratios of span to effective depth of beams for span up to 10 m as, for Continuous a) 7 b) 20 c) 26 d) 32 Ans:- choice (c) 38) The minimum reinforcement Ast to be provided in a beam depends on the fy of steel and it follows the relation: a) Ast/bd = 0.85/fy b) Ast/bd = 0.87/fy c) Ast/bd = 0.4/fy d) None of these Ans:- choice (a) 39) IS 456 recommends__________ as the minimum grade under mild environmental exposure. a) M 15 b) M 20 c) M 25 d) M 30 Ans:- choice (b) 40) The minimum shear reinforcement in the form of stirrups shall be provided such that: a) Asv/bSv >= 0.4/0.87fy b) Asv/bSv = 0.85/fy c) Asv/bSv > 0.4/0.87fy d) Asv/bSv = 0.4/0.87fy Ans:- choice (a) 41) The maximum spacing of shear reinforcement measured along the axis of the member shall not be over the least _______ for vertical stirrups a) 0.75d or 300mm b) 3d or 300mm c) d or 300mm d) None of the above Ans:- choice (a) 42) The maximum spacing of shear reinforcement measured along the axis of the member shall not be over the least of________for inclined stirrups at 45o a) 0.75d or 300mm b) 3d or 300mm c) d or 300mm d) None of these Ans:- choice (c) 43) The strengths of shear reinforcement Vus for the vertical stirrups, a) Vus =0.87fyAsv.d/Sv b) Vus =0.87fyAsv.d (sin’a+cos’a)/Sv c) Vus =0.87fyAsv.d(sin’a) d) None of the above Ans:- choice (a) 44) The strengths of shear reinforcement Vus for the inclined stirrups, a) Vus =0.87fyAsv.d/Sv b) Vus =0.87fyAsv.d (sin’a+cos’a)/Sv c) Vus =0.87fyAsv.d(sin’a) d) None of the above Ans:- choice (b) 45) The strengths of shear reinforcement Vus for the bent-up-bars, a) Vus =0.87fyAsv.d/Sv b) Vus =0.87fyAsv.d (sin’a+cos’a)/Sv c) Vus =0.87fyAsv.d(sin’a) d) None of the above Ans:- choice (c) 46) The _____ equation is given in cl. 26.2.1 of IS 456 to work out the development length of bars. a) Ld = dia.x Sigma's /4tbd b) Ld = dia.xSigma's /tbd c) Ld = Sigma's /4tbd d) None of those Ans:- choice (a)